First slide

Hydrogen Peroxide

Question

5.0 cm³ of H₂O₂ liberates 0.508 g of iodine from an acidified KI solution. The strength of H₂O₂ solution in terms of volume strength at STP is

Moderate

A

6.48 volumes
B

4.48 volumes
C

7.68 volumes
D

44.8 lit

Solution

$V_{H_{2} O_{2} = 5 ml} W_{I_{2} =} 0.508 gr {MW}_{I_{2}} = 2 \times 127 = 254 gr H_{2} O_{2} + 2 KI \overset{H^{+}}{\to} I_{2} + 2 KOH 1 mole \overset{}{\to 1 mole} ? ? \overset{}{\to} 2 \times 10^{- 3} mole \frac{2 \times 10^{- 3} \times 1}{1} M = 2 \times 10^{- 3} \times \frac{1000}{5} M = 0.4 M$
For H₂O₂
10 vol.strength = =0.893M = 1.786N = 3.03%(W/V)
?? - … = 0.4M

$\large \frac{0.4\times 10}{0.893}\;=\;\frac{4}{0.893}$

= 4.47 vol

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