5.0 cm3 of H2O2 liberates 0.508 g of iodine from an acidified KI solution. The strength of H2O2 solution in terms of volume strength at STP is

VH2O2=5ml WI2=0.508gr MWI2=2×127=254gr H2O2+2KI→H+I2+2KOH 1mole          →1mole  ??                → 2×10-3 mole 2×10-3×11 M=2×10-3×10005 M=0.4MFor H2O210 vol.strength = =0.893M = 1.786N = 3.03%(W/V)?? -  …                                              = 0.4M    = 4.47 vol