A colloidal sol is formed by moving AgNO3 and KI in 2. 1 molar ratio This colloidal sol is to be coagulatedI. NaI II. MgSO4 III. AlPO4Molar ratio of these required to coagulate 1 mole colloidal sol is

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1 1 1

1 2 3

3 2 1

6 3 2

answer is D.

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Detailed Solution

AgNO3+KI⟶AgI+KNO3 AgI+AgNO3excess⟶[AgI]Ag+Fixed layer(colloidal)⋮NO3−By [AgI] Ag + can be coagulated by negatively charged sol I- from Na, SO42− from MgSO4 and PO43− (from AlPO4. Greater the charge on anion, greater the coagulating power. (Hardy-Schulze rule)[AgI]Ag++I−⟶AgI+AgI2[AgI]Ag++SO42−⟶2AgI+Ag2SO43[AgI]Ag++PO43−⟶3AgI+Ag3PO4Thus, I- required by 1 mole colloidal sol = 1 moleSO42− required by 1 mole colloidal sol =12 mole PO43− required by 1 mole colloidal sol=13 mole Ratio =1:12:13=6:3:2

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