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a
a-p, b-q, c-s, d-r
b
a-r, b-p, c-s, d-q
c
a-s, b-p, c-q, d-r
d
a-r, b-q, c-s, d-r
answer is A.
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Detailed Solution
Strong field ligands forms inner orbitals complexes due to the anti-pairing of electrons or in simple terms we can say that they dis-obey Hunds rule of multiplicity.