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a
(p)→(iii); (q)→(i); (r)→(ii)
b
(p)→(i); (q)→(ii); (r)→(iii)
c
(p)→(iii); (q)→(ii); (r)→(i)
d
(p)→(ii); (q)→(iii); (r)→(i)
answer is A.
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Detailed Solution
Because the main reaction start with ‘A’ and ‘B’, (p) matches (iii). (q) is reverse reaction and that has eq. const. 1Kc. (r) is n times of the main equation, so its equilibrium constant is Kcn.