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Q.

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a

(p)→(iii); (q)→(i); (r)→(ii)

b

(p)→(i); (q)→(ii); (r)→(iii)

c

(p)→(iii); (q)→(ii); (r)→(i)

d

(p)→(ii); (q)→(iii); (r)→(i)

answer is A.

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Detailed Solution

Because the main reaction start with ‘A’ and ‘B’, (p) matches (iii). (q) is reverse reaction and that has eq. const. 1Kc. (r) is n times of the main equation, so its equilibrium constant is Kcn.
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