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a
total of 36 electrons on Fe2+ cation
b
sp3d2 hybrid orbitals with octahedral structure
c
total of 104 electrons
d
six sigma bonds
answer is A.
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Detailed Solution
Fe(CN)64− contains total of 36 electrons on Fe2+ cation. EAN =Z− O. S. +2× C.N. =26−2+2×6=24+12→36d2sp3 hybridisation; total of 108 electrons and 12 sigma bonds.