The composition of a sample of iron oxide is Fe0.93O, Then the percentage of the iron  present in the form of Fe (III) ?

Fe0.93O=Fe93O100 In which, Fe(II) and Fe(III) are presentlet us consider number of Fe(II) =xnumber of  Fe(III)=93-x According to electrical neutrality principlex(+2) +(93-x)(+3)+100(-2)=0            (Fe(II)  x=79 and Fe(III)=93-79=14percentage of Fe(III)=(14/93)100=15.053=15.1