In a compound C, H and N are present in the ratio of 9 : I : 3.5 by weight. If molecular weight of the compound is 108, then the molecular formula of the compound is

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C2H6N2

C3H4 N2

C6H8 N2

C9H12 N3

answer is C.

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Detailed Solution

So, empirical formula = C3H4N Empirical formula weight =(3×12+4×1+14)=54n=10854=2 Molecular formula =C3H4 N2=C6H8 N2

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