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A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is

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By Expert Faculty of Sri Chaitanya
a
C4A3
b
C2A3
c
C3A2
d
C3A4

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detailed solution

Correct option is D

Number of atoms per unit cell in hcp = 6Number of octahedral void in hcp = 6Number of anions per unit cell(A) = 6Number of octahedral voids occupied by cations(C) = 6×75100=92∴    Formula of compound = C3A4
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ctaimg

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Statement 1: Each simple cubic unit cell has 8 atoms. 
Statement 2:The total number of atoms in one cubic unit cell is 1.
 

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