A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is
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a
C4A3
b
C2A3
c
C3A2
d
C3A4
answer is D.
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Detailed Solution
Number of atoms per unit cell in hcp = 6Number of octahedral void in hcp = 6Number of anions per unit cell(A) = 6Number of octahedral voids occupied by cations(C) = 6×75100=92∴ Formula of compound = C3A4