Q.

A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is

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a

C4A3

b

C2A3

c

C3A2

d

C3A4

answer is D.

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Detailed Solution

Number of atoms per unit cell in hcp = 6Number of octahedral void in hcp = 6Number of anions per unit cell(A) = 6Number of octahedral voids occupied by cations(C) = 6×75100=92∴    Formula of compound = C3A4
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