A compound H2X with molar weight of 80 g is dissolved in a solvent having density of 0.4 g ml-1. Assuming no change in volume upon dissolution, the molality of a 3.2 molar solution is ____________

Let us consider, volume of solution = 1 litre = 1000 mL Weight of solvent = 0.4 x 1000 = 400 g Weight of solute = 80 g; Number of moles of solute = 3.2 moles Molality of solution = (m) = w2×1000Mw2×w1=n2×1000w1=3.2×1000400=8