A compound of vanadium has a magnetic moment of 1.73 BM. Find the number of unpaired electrons of vanadium ion in the compound.

Magnetic moment = n(n+2) where n- number of unpaired electrons∴ n(n+2)=1.73  n2+2n=(1.73)2 n=1Therefore, vanadium atom must have one unpaired electron and thus its electronic configuration 23V4+:1s22s22p63s23p63d1