The compressibility factor for nitrogen at 330 K and 800atm is 1.90 and at 570 K and 200 atm is 1.10. A certain mass of N2 occupies a volume of 1 dm3 at 330 K and 800 atm. calculate volume occupied by same quantity of N2 gas at 570 K and 200atm:

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1 L

2 L

3 L

4 L

answer is D.

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Detailed Solution

Z=PVnRT; 1.90=1×800n×R×330n=1×8001.90×R×330Z=1.10=V×200n×R×5701.10=V×200×1.90×R×330800×R×570V=4L

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