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Q.

The compression factor (compressibility factor) for 1 mole of a Vander-Waal's gas at 00C and 100 atm  pressure if found to be 0.5. Assuming that the volume of a gas molecule is negligible, the Vander Waal's constant 'a', The value of ‘a’ can't be

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a

0.253L2mol−2atm

b

0.53L2mol−2atm

c

1.83L2mol−2atm

d

1.253L2mol−2atm

answer is A.

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Detailed Solution

We know thatZ=PVRT⇒0.5=100×V0.0821×273⇒V=0.112 litre According to Vander Waal's equation(P+aV2)(V−b)=RT100+a(0.112)2(0.112−0)=0.0821×273a=1.253L2mol−2atm.
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