Concentrated nitric acid used in laboratory work is 68% nitric acid by mass in aqueous solution. What should be the molarity of such a sample of the nitric acid, if the density of the solution is 1.504 g mL-1 ?

68%HNO3 means 68 g of nitric acid in 100 g solution.Density of the solution= 1.504 g mL-1 Moles of HNO3=6863=1.079mol         ∵HNO3=1+14+16×3=63gmol−1 Volume of the solution =1001.504=66.5mL=0.0665L Molarity of the solution =1.0790.0665=16.23M