The concentration of H+  and concentration of OH- of a 0.1 aqueous solution of 2% ionized weak acid is [Ionic product of water = 1×10-14]

Given that Concentration of solution =0 .1Degree of ionization = 2% = 2100=0.02Ionic product of water = 1 × 10-14Concentration of H+ = Concentration of solution X degree of ionizationDegree of ionization = 0.1 ×0.02 = 2 × 10-3 MConcentration of OH- = Ionic product of waterH+= 1 × 10-142 × 10-3 = 0.5 × 10-11 = 5 × 10-12 M