Q.
Concentration of a reactant 'A' is changed from 0.044M to 0.032 M in 25 minutes, the average rate of the reaction during this interval is
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a
0.0048 mole/lit/min
b
0.00048 mole/lit/sec
c
4.8×10−4 mole/lit/min
d
0.0048 mole/lit/sec
answer is C.
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Detailed Solution
Given values are ; Concentration of a reactant ‘A’ is changed from 0.044 M to 0.032 M and time (dt) = 25 minutesAverage rate = dcdt Where, dc = change in concentration of Adt = Time taken for the change units of concentration = mole/litreUnits of time = minutes =0.044−0.03225 =0.00048 mole.lit-1min−1 =4.8×10−4 mole.lit-1 min−1
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