Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Concentration of a reactant 'A'  is changed from 0.044M to 0.032 M in 25 minutes, the average rate of the reaction during this interval is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

0.0048 mole/lit/min

b

0.00048 mole/lit/sec

c

4.8×10−4 mole/lit/min

d

0.0048 mole/lit/sec

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Given values are ; Concentration of a reactant ‘A’ is changed from 0.044 M to 0.032 M and time (dt) = 25 minutesAverage rate = dcdt Where, dc = change in concentration of Adt = Time taken for the change units of concentration = mole/litreUnits of time = minutes                        =0.044−0.03225                        =0.00048 mole.lit-1min−1                        =4.8×10−4 mole.lit-1 min−1
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring