Q.

Concentration of a reactant 'A'  is changed from 0.044M to 0.032 M in 25 minutes, the average rate of the reaction during this interval is

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a

0.0048 mole/lit/min

b

0.00048 mole/lit/sec

c

4.8×10−4 mole/lit/min

d

0.0048 mole/lit/sec

answer is C.

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Detailed Solution

Given values are ; Concentration of a reactant ‘A’ is changed from 0.044 M to 0.032 M and time (dt) = 25 minutesAverage rate = dcdt Where, dc = change in concentration of Adt = Time taken for the change units of concentration = mole/litreUnits of time = minutes                        =0.044−0.03225                        =0.00048 mole.lit-1min−1                        =4.8×10−4 mole.lit-1 min−1
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