Concentration of a reactant 'A' is changed from 0.064 M to 0.016M in 8 minutes, the average rate of the reaction during this interval is

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6×10−2mole/lit/min

0.0006 mole/lit/sec

0.006 mole/lit/min

6×10−2mole/lit/sec

answer is C.

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Detailed Solution

Given, [A]=0.064M−0.016M=0.048M Time=8 minutesAverage rate of the reaction=?Average rate=dcdt Where,dc=Change in concentrationdt = Time taken for the change=0.488=0.006mol/lit/min

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