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Q.

In a conductivity cell the two platinum electrodes, each of area 10 sq. cm is fixed 1.5 cm apart. The cell contained 0.05 N solution of a salt. If the two electrodes are just half dipped into the solution which has a resistance of 50 Ω, find equivalent conductance of the salt solution

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a

120 S cm2 eq−1

b

160 S cm2 eq−1

c

120 S m2 eq−1

d

125 S cm2 eq−1

answer is A.

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Detailed Solution

50=1Λeq×1.510/2×10000.05 ⇒λeq=120 S cm2 eq−1
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