The conductivity of a saturated solution of $BaS{O}_4$is $3.06 \times {10}^{-6} {\mathrm{ohm}}^{-1} {\mathrm{cm}}^{-1}$ and its equivalent conductance is $1.53 {\mathrm{ohm}}^{-1} {\mathrm{cm}}^{-1}$ ${\mathrm{equivalent}}^{-1}.$ The ${\mathrm{K}}_{\mathrm{sp}} \mathrm{of} \mathrm{the} {\mathrm{BaSO}}_4$ will be

• A

  $4 \times {10}^{-12}$

• B

  $2.5 \times {10}^{-9}$

• C

  $2.5 \times {10}^{-13}$

• D

  $4 \times {10}^{-6}$