The conductivity of a saturated solution of BaSO4 is 3.06 × 10-6 ohm-1 cm-1 and its equivalent conductance is 1.53 ohm-1 cm-1 equivalent-1. The Ksp of the BaSO4 will be

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4 × 10-12

2.5 × 10-9

2.5 × 10-13

4 × 10-6

answer is D.

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Detailed Solution

λm = 1000 KS = 1000 × 3.06 × 10-6S = 1.53 S = 2 × 10-3 mollitre KspBaSO4 = S2 = 2 × 10-32 = 4 × 10-6

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