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Q.

The conductivity of a saturated solution of BaSO4 is 3.06×10−6 ohm−1 cm−1 and its equivalent conductance is 1.53 ohm−1 cm2 equiv−1. The Ksp for BaSO4 will be

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a

4×10−12

b

2.5×10−13

c

25×10−9

d

10−6

answer is D.

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Detailed Solution

1.53=1000×3.06×10−6NormalityNormality = 2×10−3NMolarity = 2×10−32=10−3MKsp=10−6M
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