First slide

Boronsted-Lowry theory

Question

Conjugate acid a of water is and conjugate base of ammonia is

Easy

A

${OH}^{-}, {NH}_{2}^{-}$
B

$H_{3} O^{+}, {NH}_{2}^{-}$
C

$H_{3} O^{+}, {NH}_{4}^{+}$
D

${OH}^{-}, {NH}_{4}^{+}$

Solution

Conjugate acid = $H_{2} O + H^{+}$
$= H_{3} O^{+}$
Conjugate base = ${NH}_{3}^{} - H^{+}$
$= {NH}_{2}^{-}$

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