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Q.

Consider the conversion, CH33C-Br→alc.KOHA→peroxideHBrB ; The compound ‘B’ in the process is

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a

Iso butyl bromide

b

Tertiary butyl bromide

c

n-butyl bromide

d

Secondary butyl bromide

answer is A.

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Detailed Solution

CH33C-Br→alc.KOHCH32C=CH2→peroxideHBrCH32CH -CH2Br; Step I…Dehydrohalogenation to give isobutene;Step II… Addition of HBr by anti markonikov's rule(free radical addition) without rearrangement to give iso butyl bromide;
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Consider the conversion, CH33C-Br→alc.KOHA→peroxideHBrB ; The compound ‘B’ in the process is