Q.

Consider a 70% efficient hydrogen-oxygen fuel cell working under standard conditions at 1 bar and 298 K. Its cell reaction is H2(g)+12O2(g)→H2O(ℓ)The work derived from the cell on the consumption of 1.0 × 10–3mol of H2(g) is used to compress 1.00 mol of a monoatomic ideal gas in a thermally insulted container. What is the change in the temperature (in K) of the ideal gas ?The standard reduction potentials for the two half-cells are given below. O2(g)+4H+(aq.)+4e−→2H2O(ℓ),Eo=1.23V2H+(aq.)+2e−→H2(g),Eo=0.00VUse F = 96500 C mol–1 , R = 8.314 J mol–1K–1

Very difficult

Unlock the Full Solution and Master the Concept

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
By Expert Faculty of Sri Chaitanya

answer is 13.32.

(Detailed Solution Below)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Ecell 0=1.23−0.00=1.23VΔGcell 0=−nFEcell 0=−2×96500×1.23J∴ Work derived from this fuel cell=70100×−ΔGcell0×10−3=xJSince insulated vessel, hence q = 0From equation, for monoatomic gas, w=ΔU ⇒ x=nCV,mΔTCv,m=3R2 or,  70100×(2×96500×1.23)×10−3=1×32×8.314×ΔT∴ ΔT=13.32
ctaimg
Choose your Grade and Exam
edit icon

Connect with our

Expert Counsellors

access to India's best teachers with a record of producing top rankers year on year.

+91

We will send a verification code via OTP.

whats app icon