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Electrolytic cells

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By Expert Faculty of Sri Chaitanya
Question

Consider a 70% efficient hydrogen-oxygen fuel cell working under standard conditions at 1 bar and 298 K. Its cell reaction is 

H2(g)+12O2(g)H2O()

The work derived from the cell on the consumption of 1.0 × 10–3mol of H2(g) is used to compress 1.00 mol of a monoatomic ideal gas in a thermally insulted container. What is the change in the temperature (in K) of the ideal gas ?
The standard reduction potentials for the two half-cells are given below. 

O2(g)+4H+(aq.)+4e2H2O(),Eo=1.23V

2H+(aq.)+2eH2(g),Eo=0.00V

Use F = 96500 C mol–1 , R = 8.314 J mol–1K–1
 

Very difficult
Solution

Ecell 0=1.230.00=1.23VΔGcell 0=nFEcell 0=2×96500×1.23J

 Work derived from this fuel cell

=70100×ΔGcell0×103=xJ

Since insulated vessel, hence q = 0

From equation, for monoatomic gas,

 w=ΔU  x=nCV,mΔTCv,m=3R2 or,  70100×(2×96500×1.23)×103=1×32×8.314×ΔT ΔT=13.32


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