Consider the equilibrium PCl5(g) ⇌ PCl3(g) + Cl2(g) in a closed container. At a fixed temperature, the volume of the reaction container is halved. For this change, which of the following statements holds true regarding the equilibrium constant (Kp) and degree of dissociation(α)?
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
Neither Kp nor changes
b
Both Kp and α change
c
Kp changes, but α does not change
d
Kp does not change, but α changes
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
PCl5g⇌PCl3g+Cl2g ;Since temperature is kept constant even though volume of the container is halved, Kp remains constant.Volume of the container is halved.Thus the reaction is favoured in the direction of decrease in volume thus decomposition of PCl5 decreases.Thus degree of decomposition of PCl5(α) decreases.Therefore Kp does not change but α changes.
Not sure what to do in the future? Don’t worry! We have a FREE career guidance session just for you!
Consider the equilibrium PCl5(g) ⇌ PCl3(g) + Cl2(g) in a closed container. At a fixed temperature, the volume of the reaction container is halved. For this change, which of the following statements holds true regarding the equilibrium constant (Kp) and degree of dissociation(α)?