Consider the equilibrium PCl5(g) ⇌ PCl3(g) + Cl2(g) in a closed container. At a fixed temperature, the volume of the reaction container is halved. For this change, which of the following statements holds true regarding the equilibrium constant (Kp) and degree of dissociation(α)?

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Neither Kp nor changes

Both Kp and α change

Kp changes, but α does not change

Kp does not change, but α changes

answer is D.

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Detailed Solution

PCl5g⇌PCl3g+Cl2g ;Since temperature is kept constant even though volume of the container is halved, Kp remains constant.Volume of the container is halved.Thus the reaction is favoured in the direction of decrease in volume thus decomposition of PCl5 decreases.Thus degree of decomposition of PCl5(α) decreases.Therefore Kp does not change but α changes.

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