Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Consider the following cell reaction 2Fe(s)+O2(g)+4H+(aq)⟶ 2Fe2+(aq)+2H2O(l),E∘=1.67V At Fe2+=10−3M,pO2=0.1atm and pH=3, the cell potential at 25oC is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

1.47 V

b

1.77 V

c

1.87 V

d

1.57 V

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

The half reactions are Fe(s)⟶Fe2+(aq)+2e−×2O2(g)+4H++4e−⟶2H2O2Fe(s)+O2(g)+4H+⟶2Fe2+(aq)+2H2O(l)E=1.67−0.0594log⁡10−3210−34(0.1)=1.57V
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon