Consider the following complex ions, P, Q, and R. $$P=FeF63$$−,$$Q=VH2O62+$$ and $$R=FeH2O62+$$, the correct order of the complex ions, according to their spin only magnetic moment values (in$$ B. M.$$) is:

Question

Consider the following complex ions, P, Q, and R. $$P=FeF63$$−,$$Q=VH2O62+$$ and $$R=FeH2O62+$$, the correct order of the complex ions, according to their spin only magnetic moment values (in$$ B. M.$$) is:

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$$FeF63$$−P→$$Fe3+$$→$$d5$$ configuration, $$F-$$ is weak field ligand Unpaired electrons $$=$$ $$5$$; ∴ μ$$=55+2=5.95$$ B.M.$$VH2O62+Q$$→$$V+2$$→$$d3$$ configuration, $$H2O$$ is weak field ligand Unpaired electron $$=$$ $$3$$; ∴ μ$$=33+2=3.87$$ B.M.$$FeH2O62+R$$→$$Fe+2$$→$$d6$$ configuration, $$H2O$$ is weak field ligand Unpaired electron $$=$$ $$4$$; ∴ μ$$=44+2=4.90$$ B.M.Therefore only spin magnetic moment μ$$=nn+2B$$.M. (n$$ $$=$$ unpaired $$electron) So, μ of P > R > Q.

Consider the following complex ions, P, Q, and R. $P= {[{FeF}_{6}]}^{3 -}, Q = {[V {(H_{2} O)}_{6}]}^{2 +} and R = {[Fe {(H_{2} O)}_{6}]}^{2 +}$ , the correct order of the complex ions, according to their spin only magnetic moment values (in B. M.) is:

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Consider the following complex ions, P, Q, and R. P=FeF63−,Q=VH2O62+ and R=FeH2O62+, the correct order of the complex ions, according to their spin only magnetic moment values (in B. M.) is:

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Consider the following complex ions, P, Q, and R. $P= {[{FeF}_{6}]}^{3 -}, Q = {[V {(H_{2} O)}_{6}]}^{2 +} and R = {[Fe {(H_{2} O)}_{6}]}^{2 +}$ , the correct order of the complex ions, according to their spin only magnetic moment values (in B. M.) is: