Consider the following conversionsi) O(g) + e- → O-(g) .ΔH1ii) F(g) + e- → F-(g) .ΔH2iii) Cl(g) + e- → Cl-(g) .ΔH3iv) Na(g) → Na+(g) .ΔH4Incorrect statement is
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a
ΔH1 and ΔH2 is less negative than ΔH3
b
ΔH2 is more negative than ΔH1
c
ΔH2 , ΔH3 are negative while ΔH1 is positive
d
ΔH1 , ΔH2 and ΔH3 are negative while ΔH4 is positive
answer is C.
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Detailed Solution
O(g) + e- → O-(g) is exothermicF(g) + e- → F-(g) is exothermicCl(g) + e- → Cl-(g) is exothermicNa(g) → Na+(g) is endothermic.ΔH1 , ΔH2 and ΔH3 are negative where as ΔH4 is positiveThus 3rd option is incorrect