Consider the following E0 values E0 Fe3+ / Fe2+ = + 0.77 V E0Sn2+ / Sn = – 0.14 V Under standard conditions the potential for the reaction is

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1.68 V

0.63 V

0.91 V

1.40 V

answer is C.

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Detailed Solution

From the given cell reaction anode is Sn and cathode is Fe.= 0.77 - (-0.14) = 0.91 V

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