Consider the following Electrolytes.Maximum number of ions are present in one litre of (assume complete ionization)

For Every Solution

Volume = 1 litre

Molarity = 1M

$\therefore$ Number of moles = 1

${\mathrm{K}}_2{\mathrm{SO}}_4\rightleftharpoons 2{\mathrm{K}}^{+}+{\mathrm{SO}}_4^{-2}-3{\mathrm{N}}_{\mathrm{A}}\mathrm{ions}$

${\mathrm{AlPO}}_4\rightleftharpoons {\mathrm{Al}}^{+3}+{\mathrm{PO}}_4^{-3}-2{\mathrm{N}}_{\mathrm{A}}\mathrm{ions}$

$\mathrm{NaCl}\rightleftharpoons {\mathrm{Na}}^{+}+{\mathrm{Cl}}_{ }^{-}-2{\mathrm{N}}_{\mathrm{A}}\mathrm{ions}$

${\mathrm{FeCl}}_3\rightleftharpoons {\mathrm{Fe}}^{+3}+3{\mathrm{Cl}}_{ }^{-}-4{\mathrm{N}}_{\mathrm{A}}\mathrm{ions}$