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Q.

Consider the following electron addition process (i) O⟶ΔH1O−⟶ΔH2O2− (ii) S⟶ΔH3S−⟶ΔH4S2− (iii) P⟶ΔH5P−⟶ΔH6P2−Then which of the following statement is incorrect regarding given information

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a

ΔH5 is less negative than ΔH3 and ΔH1

b

ΔH1 is less negative than ΔH3

c

ΔH2 is more positive than ΔH4

d

None of these

answer is D.

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Detailed Solution

(i) O⟶ΔH1O−⟶ΔH2O2−  (ii) S⟶ΔH3S−⟶ΔH4S2−  (iii) P⟶ΔH5P−⟶ΔH6P2− (1) ΔH5 is less negative than ΔH3 and ΔH1 due to half field stable configuration.  (2) ΔH1 is less negative than ΔH3 due to more electron-electron repulsion in O-atom than in S-atom.  (3) ΔH2 is more positive than ΔH4 due to more electron-electron repulsion in O−-ion than in S−ion.
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