Consider the following electron addition process (i) O⟶ΔH1O−⟶ΔH2O2− (ii) S⟶ΔH3S−⟶ΔH4S2− (iii) P⟶ΔH5P−⟶ΔH6P2−Then which of the following statement is incorrect regarding given information
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a
ΔH5 is less negative than ΔH3 and ΔH1
b
ΔH1 is less negative than ΔH3
c
ΔH2 is more positive than ΔH4
d
None of these
answer is D.
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Detailed Solution
(i) O⟶ΔH1O−⟶ΔH2O2− (ii) S⟶ΔH3S−⟶ΔH4S2− (iii) P⟶ΔH5P−⟶ΔH6P2− (1) ΔH5 is less negative than ΔH3 and ΔH1 due to half field stable configuration. (2) ΔH1 is less negative than ΔH3 due to more electron-electron repulsion in O-atom than in S-atom. (3) ΔH2 is more positive than ΔH4 due to more electron-electron repulsion in O−-ion than in S−ion.