Consider the following equations,I:dpdVT=kV II:dpdVT=−kV2 III:dpdVT=−kV IV:V∝1pBoyle's law is represented by

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II and IV

II and III

I and II

I and III, IV

answer is A.

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Detailed Solution

By Boyle's law, p=kVp∝1V ∴ dpdV=−kV2=−pVV2=−pV

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