Q.

Consider the following equations,I:dpdVT=kV          II:dpdVT=−kV2 III:dpdVT=−kV        IV:V∝1pBoyle's law is represented by

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a

II and IV

b

II and III

c

I and II

d

I and III, IV

answer is A.

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Detailed Solution

By Boyle's law, p=kVp∝1V ∴ dpdV=−kV2=−pVV2=−pV
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