First slide
Nernst Equation
Question

Consider the following four electrodes:

A = Cu2+ (0.0001 M)/Cu (s)

B = Cu2+ (0.1 M)/Cu (s)

C = Cu2+ (0.01 M)/Cu (s)

D = Cu2+ (0.001 M)/Cu (s)

If the standard reduction potential of Cu is + 0.34V, the reduction potentials (in volts) of the above electrodes follow the order

Moderate
Solution

For metal electrode

Reduction potential  α   [M+n]

With increase in concentration of metal ion Reduction potential increases.

B > C > D > A.

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