Consider the following four electrodes:
A = Cu2+ (0.0001 M)/Cu (s)
B = Cu2+ (0.1 M)/Cu (s)
C = Cu2+ (0.01 M)/Cu (s)
D = Cu2+ (0.001 M)/Cu (s)
If the standard reduction potential of Cu is + 0.34V, the reduction potentials (in volts) of the above electrodes follow the order
For metal electrode
Reduction potential α [M+n]
With increase in concentration of metal ion Reduction potential increases.
B > C > D > A.