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Q.

Consider the following parallel reactions being given by A (t½ = 1.386 × 102 hours), each path being first order.If the distribution of B in the product mixture is 50%, the partial half life of A for conversion into B is

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a

231 h

b

131 h

c

115.5 h

d

31 h

answer is A.

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Detailed Solution

2k12k1+3k2=0.5 and k1+k2=0.6931.386×102=5×10−3h−1Solving k1k2=23 and k1=2×10−3h−1 and k2=3×10−3h−1t1/2(A→D)=0.693k2=0.6933×10−3=231h
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