Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Consider following physical change at temperature ST1 and T2i) H2O(l)⇌TlH2O(g);   ΔH10=xii) H2O(l)⇌T2H2O(s);   ΔH20=−yChange in internal energies of these processes are

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

IIIΔE1ΔE2x+RT1−yRT2

b

IIIΔE1ΔE2-x-RT1−y-RT2

c

IIIΔE1ΔE2x-RT1-y

d

IIIΔE1ΔE2x-y

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

(I) H2O(l)⇌T1H2O(g)Δng=( gaseous products − gaseous reactants ) = 1 - 0 = 1ΔH1o=ΔE1o+ΔngRT1x=ΔE1o+RT1∴ΔE1o=x−RT1 (II) H2O(l)⇌H2O(s)Δng=0∴ ΔH2o=ΔE2o+ΔngRT2−y=ΔE2
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring