Consider the following reaction: Given: BE(N≡N)=942 kJ mol-1;BE(N-N)=170 kJ mol-1 and BE(N=N)=420 kJ mol-1The resonance energy of the product molecule of the given reaction is  −156 kJ mol−1 . If the standard molar enthalpy of formation of  N6 (cyclic) is x kJ/mol. Then calculate the value of x150.