Consider the following reaction, 2NO2⟶2NO+O2If rate of disappearance of NO2 is 6.0×10−12mol L−1s−1then the rate of appearance of O2 is

For the reaction, 2NO2⟶2NO+O2Rate = −12dNO2dt=d[NO]2dt=dO2dt∵ −dNO2dt=6×10−12molL−1s−1∴    dO2dt=−12dNO2dt=12×6×10−12                    =3×10−12mol L−1s−1