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Consider the following reaction, 2NO2⟶2NO+O2If rate of disappearance of NO2 is 6.0×10−12mol L−1s−1then the rate of appearance of O2 is
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a
3×10−12mol L−1s−1
b
6×10−12mol L−1s−1
c
1×10−12mol L−1s−1
d
1.5×10−12mol L−1s−1
answer is A.
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Detailed Solution
For the reaction, 2NO2⟶2NO+O2Rate = −12dNO2dt=d[NO]2dt=dO2dt∵ −dNO2dt=6×10−12molL−1s−1∴ dO2dt=−12dNO2dt=12×6×10−12 =3×10−12mol L−1s−1
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