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Q.

Consider the following reactions at 300 KX  →   Y  (uncatalysed  reaction)X  →catalyst  Y (catalysed reaction)The energy of activation is lowered by 0.314  KJ  mol−1 for the catalysed reaction. The rate of reaction is_________times that of uncatalysed reaction ln1.134=0.126

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a

2.65

b

3.25

c

1.134

d

1.85 that of uncatalysed reaction.

answer is C.

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Detailed Solution

kuncat=A  e−Euncat/RT              …………(i)kcat=A  e−Ecat/RT                   …………(ii)Where,K = rate constantA = FrequencyEa = Activation energyR = Universal gas constantT = TemperaturKuncatKcat=e-Eun/RTe-Ec/RT=eEc-EunRT                =e-0.314×10008.314×300Kcat=Kun×1.134
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