Consider the following redox reaction in which compound 'X' is a product.P4 + H2O + KOH → PH3 + X.The oxidation state of phorsphorous in compound 'X' is
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a
+ 1
b
+ 3
c
+ 4
d
+ 5
answer is A.
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Detailed Solution
P4 + H2O + KOH → PH3 + X.'X' is KH2PO2KH2PO2(+1) + 2(+1) + X + 2(-2) = 0X = +1Oxidation state 'P' in KH2PO2 = +1