First slide
Molecular Orbital Theory
Question

Consider the following species : CN+,CN-,NO and CN Which one of these will have the highest bond order?

Moderate
Solution

NO:(σ1s)2,σ1s2,(σ2s)2,σ*2s2,σ2pz2,π2px2=π2py2,π2px1=π2py0

 B. O.=10-52=2.5

CN-:(σ1s)2,σ1s2,(σ2s)2,σ*2s2,π2px2=π2py2,σ2pz2

 B.O. =10-42=3

CN:(σ1s)2,σ1s2,(σ2s)2,σ2s2,π2px2=π2py2,σ2pz1

B.O·=9-42=2.5

CN+:(σ1s)2,σ1s2,(σ2s)2,σ2s2,π2px2=π2py2

 B.O. =8-42=2

 HenceCN-has highest bond order

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