Consider the given standard electrode potentials. I. K+/K=-3.02 V II. Cu2+/Cu=+0.34 V III. Hg2+/Hg=0.92 V, IV. Cr3+/Cr=-0.74 VDecreasing order of reducing power of these elements is

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I>II>III>IV

I>IV>III>II

I>IV>II>III

III>II>IV>I

answer is C.

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Detailed Solution

More the negative value of E°, higher is the reducing power. Thus, decreasing order of reducing power ofK+/K,Cu2+/Cu,Hg2+/Hg and Cr3+/Cr, is I>IV>II>III

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