Consider the heterogeneous equilibrium in a closed containerNH4HS(s) ⇌ NH3(g) + H2S(g)If more NH4HS is added to the equilibrium
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a
Partial pressure of NH3 increases
b
Partial pressure of H2S
c
Total pressure in the container increases
d
No effect on partial pressure of NH3 and H2S
answer is D.
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Detailed Solution
NH4HS(s) ⇌ NH3(g) + H2S(g)KP=NH3(g) × H2S(g)Partial pressures of NH3 and H2O do not affect NH4HS(s) because NH4HS(s) is solid for solid active mass unity.