Consider the reaction A + B →products. When the concentration of ‘B’ is kept constant and the concentration of ‘A’ is doubled, rate of the reaction becomes double the original rate. When the concentration of ‘A’ is kept constant and the concentration of ‘B' is tripled, rate of the reaction becomes one-third of original rate. The correct rate law equation is
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a
rate=K[A]1[B]0
b
rate=K[A]2[B]-1
c
rate=K[A]1[B]-1
d
rate=K[A]1[B]-2
answer is C.
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Detailed Solution
Rate = KCn ;I) B is kept constant, A is doubled, rate doubled 2x=21; x=1 ; Order w.r.t 'A' is 1. II) A is kept constant, B is tripled, rate becomes one-third 3y=13; y=-1 ; Order w.r.t 'B' is -1. Rate=KA1B-1;