Consider the reaction,4NO2g +O2g →2N2O5g, ∆rH=-111 kJ. If N2O5s is formed instead of N2O5g in the above reaction, the ∆rH value will be(Given, ∆H of sublimation for N2O5 is 54 kJ mol-1)
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.