Consider the reaction,    One mole of 'Cu' can reduce ‘X’ moles of sulphuric acid. ‘X’ is

Cu +2H2SO4 → CuSO4 +2H2O +SO2Increase in Oxidation no. of  'Cu' = 2Decrease in Oxidation no. of  'S' =2Total increase in Oxidation state of 'Cu' = Coefficient of H2SO4Total decrease in Oxidation state of  H2SO4 = Coefficient of  'Cu'∴ 2 moles of 'Cu' reduces 2 moles of sulphuric acid      1 mole of 'Cu' reduces 'X, moles of sulphuric acid                                  X = 1