Consider the reaction, PCl5g⇌PCl3g+Cl2g. Initially one mole of reactant is taken in a 10 litre closed vessel at room temperature. At an elevated temperature, PCl5 decomposes such that the number of moles of products at equilibrium are double that of reactants. Degree of decomposition of PCl5 is equal to
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a
0.75
b
0.33
c
0.25
d
0.5
answer is D.
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Detailed Solution
PCl5 ⇌ PCl3+ Cl2 Initial moles 1 - - Moles at eqbm 1-x x x Given 2nR=nP 21-x=2x x=0.5