Consider the reaction sequence from P to Q shown below. The overall yield of the major product Q from P is $$75$$%. What is the amount in grams of Q obtained from $$9.3$$ mL of P? (Use$$ density of P $$=$$ $$1.00$$ g mL–$$1$$, Molar mass of C $$=$$ $$12.0$$, H $$=$$ $$1.0$$, O $$=$$ $$16.0$$ and N $$=$$ $$14.0$$ g mol–$$1)

Question

Consider the reaction sequence from P to Q shown below. The overall yield of the major product Q from P is $$75$$%. What is the amount in grams of Q obtained from $$9.3$$ mL of P? (Use$$ density of  P $$=$$ $$1.00$$ g mL–$$1$$, Molar mass of C $$=$$ $$12.0$$, H $$=$$ $$1.0$$, O $$=$$ $$16.0$$ and N $$=$$ $$14.0$$ g mol–$$1)

Infinity Learn · Accepted Answer

Molecular weight of aniline $$=$$ M.wt. of $$C6NH7=$$ $$72$$ $$+$$ $$7$$ $$+$$ $$14$$ $$=$$ $$93density$$ of P $$=$$ $$1$$ gm ml–$$19.3$$ ml of P $$=$$ $$9.3$$ gm $$P=9.39.3=0.1$$ mole PThe mole ratio $$PhNH2$$ : $$PhN2+$$ :$$=$$ $$1$$ : $$1$$ : $$1$$ so the mole of Q formed will be $$0.1$$ mole and extent of reaction is $$100$$% but if it is $$75$$% yield.Then amount of Q $$=$$ $$0.1$$ ×$$75100=0.075molThe$$ molecular formula of Q $$=$$ $$C16H12ON2so$$ M.wt. of Q $$=$$ $$16$$ × $$12$$ $$+$$ $$12$$ × $$1$$ $$+$$ $$16$$ $$+$$ $$2$$ × $$14=$$ $$192$$ $$+$$ $$12$$ $$+$$ $$16$$ $$+$$ $$28=$$ $$248$$ gmso amount of Q $$=$$ $$248$$ × $$0.075=$$ $$18.6$$ gm

Consider the reaction sequence from P to Q shown below. The overall yield of the major product Q from P is 75%. What is the amount in grams of Q obtained from 9.3 mL of P? (Use density of P = 1.00 g mL–1, Molar mass of C = 12.0, H = 1.0, O = 16.0 and N = 14.0 g mol–1)

Detailed Solution

Get Expert Academic Guidance – Connect with a Counselor Today!