Consider the reaction sequence from P to Q shown below. The overall yield of the major product Q from P is 75%. What is the amount in grams of Q obtained from 9.3 mL of P? (Use density of  P = 1.00 g mL–1, Molar mass of C = 12.0, H = 1.0, O = 16.0 and N = 14.0 g mol–1)

Molecular weight of aniline = M.wt. of C6NH7= 72 + 7 + 14 = 93density of P = 1 gm ml–19.3 ml of P = 9.3 gm P=9.39.3=0.1 mole PThe mole ratio PhNH2 : PhN2+ := 1 : 1 : 1 so the mole of Q formed will be 0.1 mole and extent of reaction is 100% but if it is 75% yield.Then amount of Q = 0.1 ×75100=0.075molThe molecular formula of Q = C16H12ON2so M.wt. of Q = 16 × 12 + 12 × 1 + 16 + 2 × 14= 192 + 12 + 16 + 28= 248 gmso amount of Q = 248 × 0.075= 18.6 gm