Consider the redox reaction2S2O32−+I2⟶S4O62−+2I⊖

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

S2O32− gets reduced to S4O62−

S2O32− gets oxidized to S4O62−

I2 gets reduce to I⊝

I2 gets oxidized to I⊝

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

2S2O32−⟶S4O62−+2e−(Oxidation) I2+2e−⟶2I⊖ (Reduction)

Watch 3-min video & get full concept clarity