Consider the reversible reaction, Ag ⇌ Bg+Cg . Initially two moles of ‘A’ is taken in a two litre vessel. Total moles at equilibrium were found to be three. Percentage of decomposition of A(g) is

Ag ⇌ Bg+Cg Initial moles  Ag⇌Bg+Cginitial moles 2 − −Moles at equilibrum2−x x x           Total moles at equilibrium = 2 - X + X + X = 3                                                                 X = 1          % of decomposition =12×100 = 50%