Consider the thermochemical equation, $$C2H5OHl+3O2g$$→ $$2CO2g+3H2Ol$$, difference between ΔH and ΔU ∆$$H-$$∆Uof the reaction at ‘T’ kelvin is

Relation between Delta H and Delta U

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Question

Consider the thermochemical equation, $C_{2} H_{5} OH (l) + 3 O_{2} (g) \overset{}{\to} 2 {CO}_{2} (g) + 3 H_{2} O (l),$ difference between $ΔH and Δ U (∆ H - ∆ U)$ of the reaction at ‘T’ kelvin is

Easy

Solution

${Δn}_{g} = n_{P} (g) - n_{R} (g)$
= 2 - 3
= - 1
$\begin{array}{l} ΔH - ΔU = ΔnRT \\ ∆ H - ∆ U = - RT \end{array}$

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