Consider titration of NaOH solution versus 1.25 M oxalic acid solution. At the end point following burette readings were obtained. 1. 4.5ml 2. 4.5 ml 3. 4.4 ml 5. 4.4ml. 5. 4.4mlIf the volume of oxalic acid taken was 10.0ml then the molarity of the NaOH solution is …………M. (Rounded-off to the nearest integer)

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answer is 6.

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Detailed Solution

Mill eq oxalic acid = milli eq NaOH v. f×M1×v1=v.f×M2×v2,2×1.25×10=1×M2×4.4.M2=2.5×104.4=5.8M

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