First slide

Terms used in complex chemistry

Question

Considering H₂O as a weak field ligand, the number of unpaired electrons in [Mn(H₂O)₆]²⁺ will be (At. No. of Mn = 25)

Easy

A

Two
B

Four
C

Three
D

Five

Solution

$\begin{array}{l} {Mn}^{25} \to 3 d^{5} + 4 s^{2} \\ {Mn}^{2 +} \to 3 d^{5} \end{array}$
In presence of weak ligand field, there will be no pairing of electrons. So it will form a high spin complex. i.e. the number of unpaired electrons = 5.

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